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Chapter 3.1
Ordinary Homogeneous Second Order Linear Differential Equations With Constant Coefficients

In general, a second order ordinary differential equation looks like


\begin{displaymath}\frac{d^2y}{dt^2} = f \left( t, y, \frac{dy}{dt} \right)\end{displaymath}

But they are too hard to solve.

We say that a second order D.E. is linear if we can write the right-hand side in the form


\begin{displaymath}f \left( t, y, \frac{dy}{dt} \right) = g(t) - p(t)\frac{dy}{dt} - q(t)y\end{displaymath}

to obtain


y'' + p(t)y' + q(t)y = g(t)

for some functions p, q, and g of t.

If we cannot do this, we say the D.E. is nonlinear.

Examples:

Linear


\begin{displaymath}3y'' - \pi y' + \sqrt{2}y = t\end{displaymath}


\begin{displaymath}y'' + e^ty' - \cos{t}y = \sin{t}\ln{t}\end{displaymath}

Nonlinear


y y'' = 1


y'' + y' + y2 = 0

A second order initial value problem consists of the differential equation


\begin{displaymath}\frac{d^2y}{dt^2} = f \left( t, y, \frac{dy}{dt} \right)\end{displaymath}

together with two initial conditions:


\begin{displaymath}y(t_0) = y_0 \hspace{1in} y'(t_0) = y_1.\end{displaymath}





A second order linear D.E.


y'' + p(t)y' + q(t)y = g(t)

is called homogeneous if $g(t) \equiv 0$.

Otherwise, it is nonhomogeneous.

The Principle of Superposition

If y1(t) and y2(t) are solutions to the homogeneous equation


y'' + p(t)y' + q(t)y = 0,




then y(t) = c1 y1(t) + c2 y2(t) is also a solution. We say that y(t) is a linear combination of the solutions y1(t) and y2(t).




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Math 23 Winter 2000
2000-01-20